[Rdfapi-php-interest] Re: dataset->sparqlQuery() Bug?

Hi again,

i fixed the problem in ../rap/api/sparql/SparqlEngine.php in method 
_buildResultSet(). The problem was, that the value of $triple in the 
foreach loop is a Statement object if queried against the default graph 
and otherwise the value is a Quad object if queried against a named 
graph. I hope this fits to your needs and is a real bugfix without 
following a new bug!

regards, markus


/**
  * Builds the resultset.
  *
  * @param  GraphPattern $pattern
  * @param  Array        $resmodel
  * @return Array
  */
protected function _buildResultSet($pattern,$resmodel){
     // determine variables and their corresponding values
     $result = null;
     if(is_string($pattern->getSubject())){
	$n = 0;
	foreach($resmodel['trip'] as $key => $triple){
	    if(isset($resmodel['graphvar'][$key]))
		$result[$n][$resmodel['graphvar'][$key]] = $resmodel['graph'][$key];
	
	    // FIXED
	    if(isset($triple->subj)) {
		$result[$n++][$pattern->getSubject()] = $triple->subj;
	    } else {
		$result[$n++][$pattern->getSubject()] = $triple->statement->subj;
	    }
	}
     }
     if(is_string($pattern->getPredicate())){
	$n = 0;
	foreach($resmodel['trip'] as $key => $triple){
	    if(isset($resmodel['graphvar'][$key]))
		$result[$n][$resmodel['graphvar'][$key]] = $resmodel['graph'][$key];
	
	    // FIXED
	    if(isset($triple->pred)) {
		$result[$n++][$pattern->getPredicate()] = $triple->pred;
	    } else {
		$result[$n++][$pattern->getPredicate()] = $triple->statement->pred;
	    }
	}
     }
     if(is_string($pattern->getObject())){
	$n = 0;
	foreach($resmodel['trip'] as $key => $triple){
	    if(isset($resmodel['graphvar'][$key]))
		$result[$n][$resmodel['graphvar'][$key]] = $resmodel['graph'][$key];
	
	    // FIXED
	    if(isset($triple->obj)) {
		$result[$n++][$pattern->getObject()] = $triple->obj;
	    } else {
		$result[$n++][$pattern->getObject()] = $triple->statement->obj;
	    }
	}
     }

     return $result;
}